1.25=2x^2

Solution for 1.25=2x^2 equation:

1.25=2x^2

We move all terms to the left:

1.25-(2x^2)=0

a = -2; b = 0; c = +1.25;
Δ = b2-4ac
Δ = 02-4·(-2)·1.25
Δ = 10
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{10}}{2*-2}=\frac{0-\sqrt{10}}{-4}
=-\frac{\sqrt{}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{10}}{2*-2}=\frac{0+\sqrt{10}}{-4}
=\frac{\sqrt{}}{-4}
$